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Up Topic American Welding Society Services / Technical Standards & Publications / WPS Qualification rebar
- - By Duke (***) Date 03-26-2007 03:18 Edited 03-26-2007 03:43
OK,I have a D1.4 question.  I need to qualify a WPS, test will be indirect butt, Figure 6.5 (C).  I seem to be having trouble with weld length.
#6 A706 bars, (90kip tensile?) with E9018.  I get .98" for L1, does that sound right?
Parent - - By 803056 (*****) Date 03-26-2007 03:41
I maybe wrong, but I would expect the engineer to determine the required lap length needed to develop the full strength of the joint. The design drawings should provide that information.

Al
Parent - - By Duke (***) Date 03-26-2007 03:46
The Drawings specify size and length for production, but the contractor came with a WPS for 7018, Engineer wants 9018, have to requalify.
Parent - - By hogan (****) Date 03-26-2007 17:14
looks like the right number, but i have a not in my copy of the code that states the 2.4 has been changed to 5.2. the only problem is i don't remember the reason i made the note. is anyone up on d1.4 that could clue me in
Parent - - By Duke (***) Date 03-27-2007 01:39 Edited 03-27-2007 13:22
Uh, I plugged in the wrong value for (n) there are 8 welds, not 4, so weld length L1=1.96"
sounds a lot more reasonable?
I have a couple more questions...
is L1 a maximum length?
and where does it show the size of the plates that they weld the bar to, I'm assuming that the area of the plates should exceed the area of the bars.  I see in welder qual  they give the plate width as bar diameter +1", but for WPS, where is thickness?
Parent - - By pax23 (**) Date 03-27-2007 18:23
I think you were right the first time with L1=0.98". Anyway, if you were to make the assumption that n=8 instead of n=4, then L1=0.49" not L1=1.96" (n is in the denominator). Since the note to "n" states that it equals the number of welds between ONE bar and the two plates then n=4 would be correct.

This is a standard procedure qualification test not a production weld so the code stipulates the required lap not the design drawings.

I don't see "2.4" or "5.2" anywhere on this page so I do not know what that statement is referring to.

In the absence of min or max specs assume the value is nominal.

If the code does not specify the dimensions of the plate, and I don't see that it does, then you are not restricted, but certainly use a reasonable size and thickness. Use your good judgment.
Parent - By hogan (****) Date 03-27-2007 19:23
2.4 came from the equation in note 2 of figure 6.5
Up Topic American Welding Society Services / Technical Standards & Publications / WPS Qualification rebar

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