Dear Sir,
I am manufacturing a frame..I will be using 10mm plate and mig process.. I can calculate the length of fillet weld which is about 7000mm. Can anyone tell me what is the quantity in kgs that will be reqd for this length if i am using 1.2mm wire..I know that about 105 cm makes one kg of 1.2mm ER70S-6 grade of wire.
Thank you,
regards
Mukesh Agarwal
What size fillet welds will you be making?
There is a package that works with MS Excel available for this and other cost calculations at www.sterlingwelddata.com look under the products section for ToolKit A.
Thank you for your reply..I have checked the site. We have to buy the worksheet... Can u pls tell me how much weld doposit takes place per metre if we have 4 - 6 mm fillets..and welding speed is say 5 mm/ sec..
regards
I hope you buy the application it's my site.
I will try to answer this for you.
I believe what you want to know is how much filler is required to make a 6mm (1/4") fillet 7000mm (275") long.
Using the standard process efficiency for GMAW the weight of the filler required for this weld is estimated to be 1.24 kg (2.73 lbs).
So many other variables need to be considered to understand costs but I hope this helps. You tossed the torch travel speed into the question but it really has no influence on your answer.
The application shown at my site considers all the variables that influence welding costs.
I hope this helped.........let me know if this answer fits with your experience and findings.
Best regards
Neal
Thank you very much for the help. I apologise for not having written to you earlier.. Actually I was busy with the work which i have now accomplished.. Your estimate was quite close..
With regards
Mukesh Agarwal
For a fillet weld, the volume of weld is 0.5 x leg size x leg size x length of weld. For a 4mm (0.004 m) equal leg fillet, the volume of weld is 0.5 x 0.004 m x0.004 m x 7.000 m = 0.000056 cubic meters. The density of steel is 7850 kg per cubic meter. So the weight of weld is 0.4396 kg.
For a 6 mm (0.006 m) fillet: 0.5 x 0.006 m x 0.006 m x 7.000 m = 0.000126 cubic meters, and the weight is 0.000126 cubic meters x 7850 kg/cubic meter = 0.9891 kg
If you're using this to estimate how much weld wire to buy, add about 10% for wasteage.
Marty
Hello Marty
Staying in the metrics is certainly more accurate. I converted to .250" instead of .236". In my estimate I used a 10% oversize for convexity and a 98% process efficiency factor.
Great to see you on this board.
By -
Date 09-02-2000 17:16
for $54 dollars you can purchase a MIG training book that coves every aspect of MIG including weld cost simplification check out www.weldreality.com
3.08 kg
I used my application that can be found at www.sterlingwelddata.com
look under the products catagory.
I used 10mm=.394" and 7000mm=275.6" using the carbon steel variable I came up with 6.8 pounds
very close indeed.. Thank you Mr. Neal for all the help..
With kind regards
Mukesh
I have a Visual Basic application that calculates filler metal amounts for various joints, compares the cost of welding processes, and some other stuff. If you are still in need of this type of information I will email the file to you.
I would be obliged if you can kindly send me the programme ..
Thanking you
Regards
Mukesh
