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Up Topic Welding Industry / General Welding Discussion / UTS of welding rods
- - By MILLSCALE (*) Date 08-19-2017 16:43
Hello Everyone,

I don't know if this is the right place to post my question.

Anyway my question is regarding the tensile strength of electrode.

Let say for example a 6010, it says the tensile strength is 60 psi or 60,000 pounds per square inch.

Is it that if I have an area of 1 square inch weld metal of 6010, with a depth of let say 1 inch,
or let say I have 1 cubic inch of 6010 weld metal with attachments to carry loads, in order to fracture it I will need 60,000 pounds of
weight. Is this correct?

Thanks
Parent - - By 803056 (*****) Date 08-20-2017 01:27
Let's say you have two bars, each measuring 1 x 2 x 4 inches. The 1 x 2 ends are beveled so that the two bars can be joined with a complete joint penetration groove weld such the bar now measures 1 x 2 x 8 inches. The cross section through the weld (1 x 2 inches) is two square inches in area.

If the ends of the bar is loaded in tension, it should withstand a total load of 60,000 lbs times the cross sectional area of 2 square inches for a total load of 120,000 pounds.

The 60,000 pounds is the unit tensile strength of the deposited weld metal, not of the electrode itself.

Best regards - Al
Parent - By mcostello (**) Date 08-20-2017 02:45
Should be strong enough for Farm Code work.
Up Topic Welding Industry / General Welding Discussion / UTS of welding rods

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