Hello Everyone,
I don't know if this is the right place to post my question.
Anyway my question is regarding the tensile strength of electrode.
Let say for example a 6010, it says the tensile strength is 60 psi or 60,000 pounds per square inch.
Is it that if I have an area of 1 square inch weld metal of 6010, with a depth of let say 1 inch,
or let say I have 1 cubic inch of 6010 weld metal with attachments to carry loads, in order to fracture it I will need 60,000 pounds of
weight. Is this correct?
Thanks
Let's say you have two bars, each measuring 1 x 2 x 4 inches. The 1 x 2 ends are beveled so that the two bars can be joined with a complete joint penetration groove weld such the bar now measures 1 x 2 x 8 inches. The cross section through the weld (1 x 2 inches) is two square inches in area.
If the ends of the bar is loaded in tension, it should withstand a total load of 60,000 lbs times the cross sectional area of 2 square inches for a total load of 120,000 pounds.
The 60,000 pounds is the unit tensile strength of the deposited weld metal, not of the electrode itself.
Best regards - Al
Should be strong enough for Farm Code work.